Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 7 - Algebraic Fractions - Chapters 1-7 Cumulative Review Problem Set - Page 324: 24



Work Step by Step

We simplify this equation by raising each term in the expression to the power of $2$: $(9ab^{3})^{2}$ =$9^{2}\times a^{2}\times (b^{3})^{2}$ =$81\times a^{2}\times (b^{3\times2})$ =$81\times a^{2}\times (b^{6})$ =$81a^{2}b^{6}$
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