#### Answer

1

#### Work Step by Step

First, we simplify the expression within the parenthesis,
$(\frac{1}{2}+\frac{1}{3})^{0}$
=$(\frac{1(3)+1(2)}{6})^{0}$
=$(\frac{3+2}{6})^{0}$
=$(\frac{5}{6})^{0}$
According to the rules of exponents, any number raised to the power of zero is 1. Therefore,
$(\frac{5}{6})^{0}=1$