## Elementary Algebra

First, we simplify the expression within the parenthesis, $(\frac{1}{2}+\frac{1}{3})^{0}$ =$(\frac{1(3)+1(2)}{6})^{0}$ =$(\frac{3+2}{6})^{0}$ =$(\frac{5}{6})^{0}$ According to the rules of exponents, any number raised to the power of zero is 1. Therefore, $(\frac{5}{6})^{0}=1$