Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 7 - Algebraic Fractions - Chapters 1-7 Cumulative Review Problem Set - Page 324: 11



Work Step by Step

First, we simplify the expression within the parenthesis, $(\frac{1}{2}+\frac{1}{3})^{0}$ =$(\frac{1(3)+1(2)}{6})^{0}$ =$(\frac{3+2}{6})^{0}$ =$(\frac{5}{6})^{0}$ According to the rules of exponents, any number raised to the power of zero is 1. Therefore, $(\frac{5}{6})^{0}=1$
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