Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 7 - Algebraic Fractions - Chapters 1-7 Cumulative Review Problem Set - Page 324: 17

Answer

$\frac{19}{10x}$

Work Step by Step

We need to find the least common denominator and simplify the resultant expression. The LCD is $10x$, so we obtain: $\frac{7}{5x}+\frac{2}{x}-\frac{3}{2x}$ =$\frac{7(2)+2(10)-3(5)}{10x}$ =$\frac{14+20-15}{10x}$ =$\frac{34-15}{10x}$ =$\frac{19}{10x}$
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