Answer
{$-6,1$}
Work Step by Step
First, we factor the expression by using the trinomial rules of factoring. Then, we equate the resultant factors to zero.
$x^{2}+5x-6=0$
$x^{2}+6x-1x-6=0$
$x(x+6)-1(x+6)=0$
$(x+6)(x-1)=0$
$(x+6)=0$ and $(x-1)=0$
$x=-6$ and $x=1$
Therefore, the solution set is {$-6,1$}.