## Elementary Algebra

{$-6,1$}
First, we factor the expression by using the trinomial rules of factoring. Then, we equate the resultant factors to zero. $x^{2}+5x-6=0$ $x^{2}+6x-1x-6=0$ $x(x+6)-1(x+6)=0$ $(x+6)(x-1)=0$ $(x+6)=0$ and $(x-1)=0$ $x=-6$ and $x=1$ Therefore, the solution set is {$-6,1$}.