## Elementary Algebra

{$1,2$}
We use the distributive property in order to put the equation into trinomial form. We then use the rules of factoring trinomials to solve the equation: $2(x-1)-x(x-1)=0$ $2x-2-x^{2}+x=0$ $-x^{2}+x+2x-2=0$ $-x^{2}+3x-2=0$ $x^{2}-3x+2=0$ $x^{2}-1x-2x+2=0$ $x(x-1)-2(x-1)=0$ $(x-1)(x-2)=0$ $(x-1)=0$ and $(x-2)=0$ $x=1$ and $x=2$ Therefore, the solution set is {$1,2$}.