#### Answer

$-\frac{1}{16}$

#### Work Step by Step

Recall the rule: $x^{-n}=\frac{1}{x^{n}}$
We first rearrange the expression into a form that doesn't contain any negative exponents, and then we solve the expression.
$-(4)^{-2}=-\frac{1}{(4)^{2}}=-\frac{1}{4\times 4}=-\frac{1}{16}$