College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Functions and Graphs - Exercise Set 2.3 - Page 255: 72

Answer

$x$-intercept $=-\dfrac{5}{2}$ $y$-intercept $=5$

Work Step by Step

$6x-3y+15=0$ To find this equation's $y$-intercept, set $x$ equal to $0$ and solve for $y$: $6x-3y+15=0$ $6(0)-3y+15=0$ $-3y+15=0$ $-3y=-15$ $y=\dfrac{-15}{-3}$ $y=5$ To find this equation's $x$-intercept, set $y$ equal to $0$ and solve for $x$: $6x-3y+15=0$ $6x-3(0)+15=0$ $6x+15=0$ $6x=-15$ $x=-\dfrac{15}{6}$ $x=-\dfrac{5}{2}$ The intercepts of this equation are now known. The graph is shown below:
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