College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Functions and Graphs - Exercise Set 2.3 - Page 255: 29

Answer

$y=x+2$

Work Step by Step

Use the slope formula $m=\frac{y^2-y^1}{x^2-x^1}$ and the point-slope form $y-y_1=m(x-x_1)$ to solve this problem. Passing through $(-3,-1)$ and $(2,4)$ $\frac{4+1}{2+3}=1$ $y-4=1(x-2)$ $y-4=x-2$ $y=x+2$
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