## College Algebra (6th Edition)

$a)$ $y=-7$ $b)$ $m=0$ and $b=-7$ $c)$
$4y+28=0$ The slope-intercept form of the equation of a line $y=mx+b$, where $m$ is the slope of the line and $b$ is its $y$-intercept. $a)$ $4y+28=0$ Take $28$ to the right side: $4y=-28$ Take the $4$ to divide the right side: $y=-\dfrac{28}{4}$ $y=-7$ The equation is now in slope-intercept form. $b)$ Comparing the obtained equation to the slope-intercept form of the equation of a line shown at the top, it can be seen that $m=0$ and $b=-7$ The slope of the given line $m=0$ and its $y$-intercept is $(0,-7)$ $c)$ The graph is shown below: