College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Functions and Graphs - Exercise Set 2.3 - Page 255: 23

Answer

$y=-\frac{2}{3}x+2$

Work Step by Step

Use the point-slope form $y-y_1=m(x-x_1)$ to solve this problem. Slope $=-\frac{2}{3}$, passing through $(6,-2)$ $y+2=-\frac{2}{3}(x-6)$ $y+2=-\frac{2}{3}x+4$ $y=-\frac{2}{3}x+2$
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