College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Functions and Graphs - Exercise Set 2.3 - Page 255: 36

Answer

$y=-\frac{3}{2}x-\frac{3}{2}$

Work Step by Step

Use the slope formula $m=\frac{y^2-y^1}{x^2-x^1}$ and the point-slope form $y-y_1=m(x-x_1)$ to solve this problem. Passing through $(1,-3)$ with $x$-intercept $=-1$ or $(-1,0)$ $\frac{0+3}{-1-1}=-\frac{3}{2}$ $y+3=-\frac{3}{2}(x-1)$ $y+3=-\frac{3}{2}x+\frac{3}{2}$ $y=-\frac{3}{2}x-\frac{3}{2}$
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