College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Functions and Graphs - Exercise Set 2.3 - Page 255: 79

Answer

$y=-2$

Work Step by Step

$(3,y)$ and $(1,4)$ $;$ $m=-3$ The slope of a line is given by $m=\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}$, where $(x_{1},y_{1})$ and $(x_{2},y_{2})$ are two points through which the line passes. In this case, let $(x_{1},y_{1})$ be equal to $(3,y)$ and $(x_{2},y_{2})$ be equal to $(1,4)$. Substitute the known values into the formula for the slope of a line and solve for $y$: $-3=\dfrac{4-y}{1-3}$ $-3=\dfrac{4-y}{-2}$ $(-3)(-2)=4-y$ $6=4-y$ $y=4-6$ $y=-2$
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