College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Functions and Graphs - Exercise Set 2.3 - Page 255: 37

Answer

$y=8x+4$

Work Step by Step

Use the slope formula $m=\frac{y^2-y^1}{x^2-x^1}$ and the point-slope form $y-y_1=m(x-x_1)$ to solve this problem. $x$-intercept $=-\frac{1}{2}$ or $(-\frac{1}{2},0)$ and $y$-intercept $=4$ or $(0,4)$ $\frac{4-0}{0+\frac{1}{2}}=8$ $y-0=8(x+\frac{1}{2})$ $y-0=8x+4$ $y=8x+4$
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