Answer
$x$-intercept $=-\dfrac{3}{2}$
$y$-intercept $=6$
Work Step by Step
$8x-2y+12=0$
To find this equation's $x$-intercept, set $y$ equal to $0$ and solve for $x$:
$8x-2y+12=0$
$8x-2(0)+12=0$
$8x+12=0$
$8x=-12$
$x=-\dfrac{12}{8}$
$x=-\dfrac{3}{2}$
To find this equation's $y$-intercept, set $x$ equal to $0$ and solve for $y$:
$8x-2y+12=0$
$8(0)-2y+12=0$
$-2y+12=0$
$-2y=-12$
$y=\dfrac{-12}{-2}$
$y=6$
The intercepts of this equation are now known. The graph is shown below:
