College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Functions and Graphs - Exercise Set 2.3 - Page 255: 61

Answer

$a)$ $y=-\dfrac{2}{3}x+6$ $b)$ $m=-\dfrac{2}{3}$ and $b=6$ $c)$

Work Step by Step

$2x+3y-18=0$ The slope-intercept form of the equation of a line $y=mx+b$, where $m$ is the slope of the line and $b$ is its $y$-intercept $a)$ $2x+3y-18=0$ Take $2x$ and $18$ to the right side of the equation: $3y=-2x+18$ Take the $3$ to divide the right side: $y=-\dfrac{2}{3}x+6$ The equation is now in slope-intercept form. $b)$ Comparing the obtained equation to the slope-intercept form of the equation of a line shown at the top, it can be seen that $m=-\dfrac{2}{3}$ and $b=6$ The slope of the given line is $m=-\dfrac{2}{3}$ and its $y$-intercept is $(0,6)$ $c)$ The graph is shown below:
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