## College Algebra (6th Edition)

$a)$ $y=-3x+5$ $b)$ $m=-3$ and $b=5$ $c)$
$3x+y-5=0$ The slope-intercept form of the equation of a line is $y=mx+b$, where $m$ is the slope of the line and $b$ is its $y$-intercept $a)$ $3x+y-5=0$ Take $3x$ and $5$ to the right side of the equation: $y=-3x+5$ The equation is now in slope-intercept form. $b)$ Comparing the obtained equation to the slope-intercept form of the equation of a line shown at the top, it can be seen that $m=-3$ and $b=5$. The slope of the line given is $m=-3$ and its $y$-intercept is $(0,5)$ $c)$ The graph is shown below: