Answer
$y=-\frac{4}{3}x+2$
Work Step by Step
Use the slope formula $m=\frac{y^2-y^1}{x^2-x^1}$ and the point-slope form $y-y_1=m(x-x_1)$ to solve this problem.
Passing through $(-3,6)$ and $(3,-2)$
$\frac{-2-6}{3+3}=-\frac{4}{3}$
$y-6=-\frac{4}{3}(x+3)$
$y-6=-\frac{4}{3}x-4$
$y=-\frac{4}{3}x+2$