## College Algebra (6th Edition)

Published by Pearson

# Chapter 2 - Functions and Graphs - Exercise Set 2.3 - Page 255: 62

#### Answer

$a)$ $y=-\dfrac{2}{3}x-2$ $b)$ $m=-\dfrac{2}{3}$ and $b=-2$ $c)$

#### Work Step by Step

$4x+6y+12=0$ The slope-intercept form of the equation of a line $y=mx+b$, where $m$ is the slope of the line and $b$ is its $y$-intercept $a)$ $4x+6y+12=0$ Take $4x$ and $12$ to the right side of the equation: $6y=-4x-12$ Take the $6$ to divide the right side: $y=-\dfrac{2}{3}x-2$ The equation is now in slope-intercept form. $b)$ Comparing the obtained equation to the slope-intercept form of the equation of a line shown at the top, it can be seen that $m=-\dfrac{2}{3}$ and $b=-2$ The slope of the given line is $m=-\dfrac{2}{3}$ and its $y$-intercept is $(0,-2)$ $c)$ The graph is shown below:

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