College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.5 - Page 160: 60


x=3 or -$\frac{1}{2}$

Work Step by Step

2x$^2$+5x-3=0 x$^2$+$\frac{5}{2}$x=$\frac{3}{2}$ (x+$\frac{5}{4}$)$^2$=$\frac{49}{16}$ x+$\frac{5}{4}$= +/- $\frac{7}{4}$ x=3 or -$\frac{1}{2}$
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