College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.5 - Page 160: 48



Work Step by Step

To complete the square, add a term that is the square of half the coefficient of $x$ to both sides of the equation, and factor the left side. Then use the square root property to simplify both sides, and then isolate $x$. $x^2+6x=-8$ $(\frac{6}{2})^2=(3)^2$ $x^2+6x+(3)^2=-8+(3)^2$ $x^2+6x+9=-8+9$ $x^2+6x+9=1$ $(x+3)^2=1$ $x+3=±1$ $x=-3±1$ $x=-4,-2$
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