## College Algebra (6th Edition)

$x=\frac{-2}{3},\frac{-1}{3}$
$9x^{2}+9x+2=0$ $9x^{2}+6x+3x+2=0$ $3x(3x+2)+1(3x+2)=0$ $(3x+1)(3x+2)=0$ $x=\frac{-2}{3},\frac{-1}{3}$ Multiply the coefficient of the first term by the third term and then do trial and error. Then group and find the greatest common factors of each group to get the complete factorization. Then solve for $x$ by setting each value equal to zero.