Answer
$x=-3-\sqrt {14}, -3+\sqrt {14}$
Work Step by Step
To complete the square, add a term that is the square of half the coefficient of $x$ to both sides of the equation, and factor the left side. Then use the square root property to simplify both sides, and then isolate $x$.
$x^2+6x-5=0$
$(\frac{6}{2})^2=(3)^2$
$x^2+6x-5+5+(3)^2=5+(3)^2$
$x^2+6x+(3)^2=5+(3)^2$
$x^2+6x+9=5+9$
$x^2+6x+9=14$
$(x+3)^2=14$
$x+3=±\sqrt {14}$
$x=-3±\sqrt {14}$
$x=-3-\sqrt {14}, -3+\sqrt {14}$
