College Algebra (6th Edition)

Published by Pearson

Chapter 1 - Equations and Inequalities - Exercise Set 1.5 - Page 160: 33

Answer

$x=\frac{-8-3\sqrt3}{2},\frac{-8+3\sqrt3}{2}$

Work Step by Step

$(2x+8)^{2}=27$ $2x+8=\sqrt 27$ $2x+8=-\sqrt 27$ $x=\frac{-8-3\sqrt3}{2},\frac{-8+3\sqrt3}{2}$ Take the square root of both sides. Then isolate $x$ from both of the resulting equations to get two answers.

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