College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.5 - Page 160: 50

Answer

$x=-6,2$

Work Step by Step

To complete the square, add a term that is the square of half the coefficient of $x$ to both sides of the equation, and factor the left side. Then use the square root property to simplify both sides, and then isolate $x$. $x^2+4x=12$ $(\frac{4}{2})^2=(2)^2$ $x^2+4x+(2)^2=12+(2)^2$ $x^2+4x+4=12+4$ $x^2+4x+4=16$ $(x+2)^2=16$ $x+2=±4$ $x=-2±4$ $x=-6,2$
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