College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.5 - Page 160: 11



Work Step by Step

Distribute by multiplying on the left side. Then put all terms on the left side to make the other side zero. Then find the GCF of the terms and set both resulting terms equal to zero to solve for $x$. $2x(x-3)=5x^2-7x$ $2x^2-6x=5x^2-7x$ $-3x^2+x=0$ $x(-3x+1)=0$ $x=0$ $-3x+1=0$ $-3x=-1$ $x=\frac{1}{3}$ $x=0,\frac{1}{3}$
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