College Algebra (6th Edition)

$x=-10,-1$
$x^{2}=-11x-10$ $x^{2}+11x+10=0$ $(x+1)(x+10)=0$ $x=-10,-1$ Get all the terms on one side to make the other side zero. Then factor by trial and error for this trinomial. Then solve for $x$ by setting each value equal to zero.