College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.5 - Page 160: 4

Answer

$x=-10,-1$

Work Step by Step

$x^{2}=-11x-10$ $x^{2}+11x+10=0$ $(x+1)(x+10)=0$ $x=-10,-1$ Get all the terms on one side to make the other side zero. Then factor by trial and error for this trinomial. Then solve for $x$ by setting each value equal to zero.
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