## College Algebra (6th Edition)

$x=3-i\sqrt 5, 3+i\sqrt 5$
$(x-3)^{2}=-5$ $x-3=\sqrt -5= 3-i\sqrt 5, 3+i\sqrt 5$ $x=3-i\sqrt 5, 3+i\sqrt 5$ Take the square root of both sides. Then isolate $x$ from both of the resulting equations to get two answers.