## College Algebra (6th Edition)

$x=-4+\sqrt -7,-4+\sqrt 7$
$3(x+4)^{2}=21$ $(x+4)^{2}=7$ $x+4=\sqrt 7$ $x+4=\sqrt -7$ $x=-4+\sqrt -7,-4+\sqrt 7$ Divide both sides. Then take the square root of both sides. Then isolate $x$ from both of the resulting equations to get two answers.