College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.5 - Page 160: 1


The solutions are $x=5$ and $x=-2$

Work Step by Step

$x^{2}-3x-10=0$ Solve this equation by factoring: $(x-5)(x+2)=0$ Set both factors equal to $0$ and solve each individual equation for $x$: $x-5=0$ $x=5$ $x+2=0$ $x=-2$ The solutions are $x=5$ and $x=-2$
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