## College Algebra (6th Edition)

The solutions are $x=5$ and $x=-2$
$x^{2}-3x-10=0$ Solve this equation by factoring: $(x-5)(x+2)=0$ Set both factors equal to $0$ and solve each individual equation for $x$: $x-5=0$ $x=5$ $x+2=0$ $x=-2$ The solutions are $x=5$ and $x=-2$