Answer
$25$; $(x-5)^2$
Work Step by Step
To complete the square, add a term that is the square of half the coefficient of $x$ in the middle term. Then factor by trial and error.
$x^2-10x$
$(-\frac{10}{2})^2=(-5)^2=25$
$x^2-10x+25$
$(x-5)^2$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 1 - Equations and Inequalities - Exercise Set 1.5 - Page 160: 37
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