College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.5 - Page 160: 36

Answer

$64$; $(x+8)^2$

Work Step by Step

To complete the square, add a term that is the square of half the coefficient of $x$ in the middle term. Then factor by trial and error. $x^2+16x$ $(\frac{16}{2})^2=8^2=64$ $x^2+16x+64$ $(x+8)^2$
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