Answer
=36.0 V
Work Step by Step
We note that we obtain the maximum value in Formula when we set
$
t=\frac{\pi}{2 \omega_d}\\=\frac{1}{4 f}=\frac{1}{4(60)}\\=0.00417 \mathrm{~s}
$
or $4.17 \mathrm{~ms}$. The result is
$\varepsilon_m \sin (\pi / 2)\\=\varepsilon_m \sin \left(90^{\circ}\right)\\=36.0 \mathrm{~V}$.
