Answer
The circuit is capacitive.
Work Step by Step
It is given that the current leads the emf by $~~0.982~rad$
Therefore, $\phi \lt 0$ which means that $~~X_C \gt X_L$
Therefore, the circuit is capacitive.
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 31 - Electromagnetic Oscillations and Alternating Current - Problems - Page 940: 75c
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