Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 31 - Electromagnetic Oscillations and Alternating Current - Problems - Page 940: 85b

Answer

$U=17.9$ pJ

Work Step by Step

We know that: $U=\frac{1}{2}LI^2$ We plug in the known values to obtain: $U=\frac{1}{2}(0.689\times 10^{-6})(7.20\times 10^{-3})^2=17.9\times 10^{-12}=17.9pJ$
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