Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 31 - Electromagnetic Oscillations and Alternating Current - Problems - Page 940: 84c

Answer

$C=21.9nF$

Work Step by Step

$ C=\left((2 \pi(6000))^2 L\right)^{-1}\\=21.9 \mathrm{nF} . $
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