Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 31 - Electromagnetic Oscillations and Alternating Current - Problems - Page 940: 87c

Answer

$C=1.49 \times 10^{-5} \mathrm{~F} $

Work Step by Step

$ \begin{aligned} C & =\frac{I_2}{2 \omega_d \varepsilon_m\left(1-\tan \phi_1 / \tan \phi_0\right)}=\frac{2.00 \mathrm{~A}}{2(2 \pi)(60.0 \mathrm{~Hz})(120 \mathrm{~V})\left(1-\tan 10.0^{\circ} / \tan \left(-20.0^{\circ}\right)\right)} \\\\ & =1.49 \times 10^{-5} \mathrm{~F} . \end{aligned} $
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