Answer
The total energy in the circuit is $~~2.14\times 10^{-11}~J$
Work Step by Step
We can find the energy when all the energy is stored in the magnetic field:
$U_B = \frac{L~i^2}{2}$
$U_B = \frac{(2.41\times 10^{-6}~H)~(4.21\times 10^{-3}~A)^2}{2}$
$U_B = 2.14\times 10^{-11}~J$
The total energy in the circuit is $~~2.14\times 10^{-11}~J$
