Answer
$R=165Ω$
Work Step by Step
$
\text { } R=\frac{-\varepsilon_m}{I_2 \tan \phi_{\mathrm{o}}}\\=\frac{-120 \mathrm{~V}}{(2.00 \mathrm{~A}) \tan \left(-20.0^{\circ}\right)}\\=165 \Omega \text { }
$
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