Answer
The maximum charge on the capacitor is $~~8.22\times 10^{-8}~C$
Work Step by Step
In part (b), we found that the total energy in the circuit is $~~2.14\times 10^{-11}~J$
We can find the charge when all the energy is stored in the electric field:
$U_E = \frac{q^2}{2C}$
$q^2 = 2C~U_E$
$q = \sqrt{2C~U_E}$
$q = \sqrt{(2)(158\times 10^{-6}~F)~(2.14\times 10^{-11}~J)}$
$q = 8.22\times 10^{-8}~C$
The maximum charge on the capacitor is $~~8.22\times 10^{-8}~C$
