Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 31 - Electromagnetic Oscillations and Alternating Current - Problems - Page 940: 84a

Answer

$R = 707~\Omega$

Work Step by Step

Ir is given that the impedance is $~~Z = 1000~\Omega$ It is given that $\phi = 45^{\circ}$ We can find an expression for $X_L - X_C$: $tan~\phi = \frac{X_L-X_C}{R}$ $X_L-X_C = R~tan~\phi$ We can find the resistance $R$: $Z = \sqrt{R^2+(X_L-X_C)^2} = 1000~\Omega$ $\sqrt{R^2+(R~tan~\phi)^2} = 1000~\Omega$ $\sqrt{R^2~(1+~tan^2~\phi)} = 1000~\Omega$ $R^2~(1+~tan^2~\phi) = (1000~\Omega)^2$ $R^2 = \frac{(1000~\Omega)^2}{1+~tan^2~\phi}$ $R = \frac{1000~\Omega}{\sqrt{1+~tan^2~\phi}}$ $R = \frac{1000~\Omega}{\sqrt{1+~tan^2~45^{\circ}}}$ $R = \frac{1000~\Omega}{\sqrt{2}}$ $R = 707~\Omega$
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