Answer
$ϕ=45.0^{∘}$
Work Step by Step
With $V_C=V_L / 2.00$ and $V_R=V_L / 2.00$,
We can find the phase constant to be
$
\phi=\tan ^{-1}\left(\frac{V_L-V_L / 2.00}{V_L / 2.00}\right)\\=\tan ^{-1}(1.00)\\=45.0^{\circ} .
$
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