Answer
$T = 1.09~ms$
Work Step by Step
Note that $~~\omega = \frac{1}{\sqrt{L~C}}$
We can find the period of oscillation:
$T = \frac{2\pi}{\omega}$
$T = 2\pi~\sqrt{L~C}$
$T = (2\pi)~\sqrt{(3.00\times 10^{-3}~H)~(10.0\times 10^{-6}~F)}$
$T = 1.09~ms$
