Answer
$2.8kV$
Work Step by Step
The breakdown potential of capacitor is :
$=(14 k \frac{V}{mm})(3.8 cm-3.6 cm)$
$= 2.8kV$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 25 - Capacitance - Problems - Page 742: 44b
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