Answer
$V_1 = 50.0~V$
Work Step by Step
In part (d), we found that $q_1 = 500~\mu C$
We can find $V_1$:
$V_1 = \frac{q_1}{C_1}$
$V_1 = \frac{500~\mu C}{10.0~\mu F}$
$V_1 = 50.0~V$
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