Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 25 - Capacitance - Problems - Page 742: 32e

Answer

$u=1.6\frac{J}{m^3}$

Work Step by Step

The energy density is given as $u=\frac{1}{2}\epsilon_{\circ}E^2$ $u=\frac{1}{2}(8.85\times10^{-12})(600000)^2$ $u=1.6\frac{J}{m^3}$
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