Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 25 - Capacitance - Problems - Page 742: 42b

Answer

$2.8\times10^{-10}\,F$ or $280\,pF$

Work Step by Step

Given/known: $\kappa=5.6,$ $\varepsilon_{0}=8.854\times10^{-12}\,F/m,$ $A=0.35\,m^{2}$ and $d=0.062\,m$ (from part a). Recall: $C=\frac{\kappa\varepsilon_{0}A}{d}$ Result: $C=\frac{5.6\times8.854\times10^{-12}F/m\times0.35\,m^{2}}{0.062\,m}=2.8\times10^{-10}\,F$
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