Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 25 - Capacitance - Problems - Page 742: 32c

Answer

$U=6.4 \mu C$

Work Step by Step

The stored energy is given as $U=\frac{1}{2}CV^2$ putting the values, we get $U=\frac{1}{2}(3.54\times10^{-11})(600)^2$ $U=6.4\times10^{-6}J$ $U=6.4 \mu C$
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