Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 25 - Capacitance - Problems - Page 742: 34e

Answer

$V_1 = 33.3~V$

Work Step by Step

In part (d), we found that $q_1 = 3.33\times 10^{-4}~C$ We can find $V_1$: $V_1 = \frac{q_1}{C_1}$ $V_1 = \frac{3.33\times 10^{-4}~C}{10.0\times 10^{-6}~F}$ $V_1 = 33.3~V$
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