Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 25 - Capacitance - Problems - Page 742: 32a

Answer

$C=35pF$

Work Step by Step

We know that $C=\frac{A\epsilon_{\circ}}{d}$ We are given that $A=4 cm^2=4\times10^{-4}m^2$ and $d=1mm=1\times10^{-3}m$ Thus, we obtain: $C=\frac{4\times10^{-4}(8.85\times10^{-12})}{1\times10^{-3}}$ $C=3.5\times10^{-12}=35pF$ $C=35pF$
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