Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 25 - Capacitance - Problems - Page 742: 29

Answer

$C=72F$

Work Step by Step

Recall the following equation: $U=\frac{1}{2}CV^2$ This simplfies to: $C=\frac{2U}{V^2}$ We plug in the known values to obtain: $C=\frac{2(3.6\times10^7)}{(1000)^2}$ $C=72F$
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